A wooden cube of side 10 cm has mass 700g. What part of it remains above water surface while floating on water?This is a numerical of floatation.

A wooden cube of side 10 cm has mass 700g. What part of it remains above water surface while floating on water?This is a numerical of floatation.

A wooden cube of side 10 cm has mass 700g. What part of it remains above water surface while floating on water?This is a numerical of floatation.

A wooden cube of side 10 cm has mass 700g. What part of it remains above water surface while floating on water?This is a numerical of floatation.
Let us say the volume that is in water is V1 and the total volume of the cube is V.In Archimedes law he has stated that the weight of the volume of fluid displaced by the body is equal to the weight of the immersed body. Weight of the displaced fluid `= V1*rho` Therefore;`0.7*9.81 = V1*rho*9.81`       `V1 = 7xx10^(-4) m^3` Volume of cube `(V) = (10xx10^(-2))^3m^3 = 10^(-3)m^` 3 Fraction of cube in water `= (V1)/V = (7xx10^(-4))/10^(-3) = 0.7`  So 70% of the cube is in water.OR 0.7 of the total volume of cube is under water.