# What is the Na+ ion concentration in the solution formed by mixing 20. mL of 0.10 M Na2SO4 solution with 50. mL of 0.30 M Na3PO4 solution?

What is the Na+ ion concentration in the solution formed by mixing 20. mL of 0.10 M Na2SO4 solution with 50. mL of 0.30 M Na3PO4 solution?

What is the Na+ ion concentration in the solution formed by mixing 20. mL of 0.10 M Na2SO4 solution with 50. mL of 0.30 M Na3PO4 solution?

What is the Na+ ion concentration in the solution formed by mixing 20. mL of 0.10 M Na2SO4 solution with 50. mL of 0.30 M Na3PO4 solution?
`Na_2SO_4 rarr 2Na^++SO_4^(2-)“Na_3PO_4 rarr 3Na^++PO_4^(3-)`  Mole ratio`Na_2SO_4:Na^+ = 1:2` `Na_3PO_4:Na^+ = 1:3`  Amount of `Na_2SO_4` used `= 0.1/1000xx20` Amount of `Na^+` from `Na_2SO_4 = 0.1/1000xx20xx2`  Amount of `Na_3PO_4` used `= 0.3/1000xx50`Amount of `Na^+` from `Na_3PO_4 = 0.3/1000xx50xx3`  Total `Na^+`  moles= (`Na^+` from `Na_2SO_4` )+(`Na^+` from `Na_3PO_4` )`= 0.1/1000xx20xx2+0.3/1000xx50xx3` = 0.049 So this 0.049 moles of  `Na^+` is (20+50) = 70ml of solution. Concentration of `Na^+ = 0.049/70xx1000 M = 0.7M`  So the final concentration of `Na^+` is 0.7M.